HETERONUCLEAR AND HETEROVALENT DIPHENYLPHOSPHIDO-BRIDGED COMPLEXES OF RHODIUM, IRIDIUM AND RUTHENIUM - CRYSTAL-STRUCTURE OF [(C5ME5)CLRH(MU-CL)(MU-PPH2)RH(COD)].1/2ET2O (COD = 1,5-CYCLOOCTADIENE)

被引:17
作者
ESTEBAN, M [1 ]
PEQUERUL, A [1 ]
CARMONA, D [1 ]
LAHOZ, FJ [1 ]
MARTIN, A [1 ]
ORO, LA [1 ]
机构
[1] UNIV ZARAGOZA,CSIC,INST CIENCIA MAT ARAGON,DEPT QUIM INORGAN,E-50009 ZARAGOZA,SPAIN
关键词
D O I
10.1016/0022-328X(91)86254-N
中图分类号
O61 [无机化学];
学科分类号
070301 ; 081704 ;
摘要
Mononuclear complexes of formulae [LMCl2(HPRR')], [LMCl(HPR2)2]BF4 and [LM(acac)-(HPR2)]BF4 (M = Rh, Ir; L = C5Me5. M = Ru; L = p-Cymene; R = Ph, H; R' = H; Hacac = acetylacetone but not in all possible combinations) have been prepared from the corresponding [{LMCl}2(mu-Cl)2] or [LMCl(acac)] and HPRR'. Complexes [LMCl2(HPPh2)] [L = C5Me5; M = Rh (I), Ir (IV), L = p-Cymene; M = Ru (VII)] react with [M'(mu-OMe)(diolefin)]2 (M' = Rh; diolefin = tetrafluorobenzobarrelene (TFB), 1,5-cyclooctadiene (COD). M' = Ir; diolefin = COD) to yield diphenylphosphido-bridged complexes of formula [LMCl2(mu-PPh2)M'(diolefin)]. The structure of [(C5Me5)ClRh(mu-Cl)(mu-PPh2)Rh(COD)].1/2Et2O has been determined by X-ray diffraction methods. The complex consists of two moieties, (C5Me5)RhCl and Rh(COD), doubly-bridged by a diphenylphosphido group and a chlorine atom. The two rhodium atoms are separated by 3.3657(6) angstrom.
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页码:421 / 434
页数:14
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