For any distinct two primes p1≡p2≡3\documentclass[12pt]{minimal}
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\begin{document}$$p_1\equiv p_2\equiv 3$$\end{document}(mod4)\documentclass[12pt]{minimal}
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\begin{document}$$(\text {mod }4)$$\end{document}, let h(-p1)\documentclass[12pt]{minimal}
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\begin{document}$$h(-p_1)$$\end{document}, h(-p2)\documentclass[12pt]{minimal}
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\begin{document}$$h(-p_2)$$\end{document} and h(p1p2)\documentclass[12pt]{minimal}
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\begin{document}$$h(p_1p_2)$$\end{document} be the class numbers of the quadratic fields Q(-p1)\documentclass[12pt]{minimal}
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\begin{document}$$\mathbb {Q}(\sqrt{-p_1})$$\end{document}, Q(-p2)\documentclass[12pt]{minimal}
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\begin{document}$$\mathbb {Q}(\sqrt{-p_2})$$\end{document} and Q(p1p2)\documentclass[12pt]{minimal}
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\begin{document}$$\mathbb {Q}(\sqrt{p_1p_2})$$\end{document}, respectively. Let ωp1p2:=(1+p1p2)/2\documentclass[12pt]{minimal}
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\begin{document}$$\omega _{p_1p_2}:=(1+\sqrt{p_1p_2})/2$$\end{document} and let Ψ(ωp1p2)\documentclass[12pt]{minimal}
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\begin{document}$$\varPsi (\omega _{p_1p_2})$$\end{document} be the Hirzebruch sum of ωp1p2\documentclass[12pt]{minimal}
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\begin{document}$$\omega _{p_1p_2}$$\end{document}. We show that h(-p1)h(-p2)≡h(p1p2)Ψ(ωp1p2)/n\documentclass[12pt]{minimal}
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\begin{document}$$h(-p_1)h(-p_2)\equiv h(p_1p_2)\varPsi (\omega _{p_1p_2})/n$$\end{document}(mod8)\documentclass[12pt]{minimal}
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\begin{document}$$(\text {mod }8)$$\end{document}, where n=6\documentclass[12pt]{minimal}
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\begin{document}$$n=6$$\end{document} (respectively, n=2\documentclass[12pt]{minimal}
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\begin{document}$$n=2$$\end{document}) if minp1,p2>3\documentclass[12pt]{minimal}
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\begin{document}$$min {p1, p2} > 3$$\end{document} (respectively, otherwise). We also consider the real quadratic order with conductor 2 in Q(p1p2)\documentclass[12pt]{minimal}
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\begin{document}$$\mathbb {Q}(\sqrt{p_1p_2})$$\end{document}.