There are many refinements of list coloring, one of which is the choosability with union separation. Let k, s be positive integers and let G be a graph. A (k,k+s)\documentclass[12pt]{minimal}
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\begin{document}$$(k,k+s)$$\end{document}-list assignment of G is a mapping L assigning each vertex v∈V(G)\documentclass[12pt]{minimal}
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\begin{document}$$v\in V(G)$$\end{document} a list of colors L(v) such that |L(v)|≥k\documentclass[12pt]{minimal}
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\begin{document}$$|L(v)|\ge k$$\end{document} for each vertex v∈V(G)\documentclass[12pt]{minimal}
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\begin{document}$$v\in V(G)$$\end{document}, and |L(u)∪L(v)|≥k+s\documentclass[12pt]{minimal}
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\begin{document}$$|L(u)\cup L(v)|\ge k+s$$\end{document} for each edge uv∈E(G)\documentclass[12pt]{minimal}
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\begin{document}$$uv\in E(G)$$\end{document}. If for each (k,k+s)\documentclass[12pt]{minimal}
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\begin{document}$$(k,k+s)$$\end{document}-list assignment L of G, G admits a proper coloring φ\documentclass[12pt]{minimal}
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\begin{document}$$\varphi $$\end{document} such that φ(v)∈L(v)\documentclass[12pt]{minimal}
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\begin{document}$$\varphi (v)\in L(v)$$\end{document} for each v∈V(G)\documentclass[12pt]{minimal}
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\begin{document}$$v\in V(G)$$\end{document}, then G is (k,k+s)\documentclass[12pt]{minimal}
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\begin{document}$$(k,k+s)$$\end{document}-choosable. Let G be a planar graph. In this paper, we prove: (1) if G contains no chorded 4-cycle, then G is (3, 8)-choosable; (2) if G contains neither intersecting triangles nor intersecting 4-cycles, then G is (3, 6)-choosable.
