This article is a part of the theory developed by the author in which the following problem is solved under natural assumptions: to find necessary and sufficient conditions under which the union of at most countable family of algebras on a certain set X is equal to P(X)\documentclass[12pt]{minimal}
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\begin{document}$\mathcal{P}(X)$\end{document}. Here the following new result is proved. Let {Aλ}λ∈Λ\documentclass[12pt]{minimal}
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\begin{document}$\{\mathcal{A}_{\lambda }\}_{\lambda \in \Lambda }$\end{document} be a finite collection of algebras of sets given on a set X with #(Λ)=n>0\documentclass[12pt]{minimal}
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\begin{document}$\# (\Lambda ) =n>0$\end{document}, and for each λ there exist at least 103n+2n3\documentclass[12pt]{minimal}
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\begin{document}$\frac{10}{3}n+\sqrt{\frac{2n}{3}}$\end{document} pairwise disjoint sets belonging to P(X)∖Aλ\documentclass[12pt]{minimal}
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\begin{document}$\mathcal{P}(X)\setminus\mathcal{A}_{\lambda }$\end{document}. Then there exists a family {Uλ1,Uλ2}λ∈Λ\documentclass[12pt]{minimal}
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\begin{document}$\{U^{1}_{\lambda }, U^{2}_{\lambda }\}_{\lambda \in \Lambda }$\end{document} of pairwise disjoint subsets of X (Uλi∩Uλ′j=∅\documentclass[12pt]{minimal}
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\begin{document}$U^{i}_{\lambda }\cap U^{j}_{\lambda '}=\emptyset$\end{document} except the case λ=λ′\documentclass[12pt]{minimal}
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\begin{document}$\lambda =\lambda '$\end{document}, i=j\documentclass[12pt]{minimal}
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\begin{document}$i=j$\end{document}); and for each λ the following holds: if Q∈P(X)\documentclass[12pt]{minimal}
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\begin{document}$Q\in \mathcal{P}(X)$\end{document} and Q contains one of the two sets Uλ1\documentclass[12pt]{minimal}
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\begin{document}$U^{1}_{\lambda }$\end{document}, Uλ2\documentclass[12pt]{minimal}
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\begin{document}$U^{2}_{\lambda }$\end{document}, and its intersection with the other set is empty, then Q∉Aλ\documentclass[12pt]{minimal}
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\begin{document}$Q\notin \mathcal{A}_{\lambda }$\end{document}.