On sums of a prime and four prime squares in short intervals

For every sufficiently large odd integer Nnot equivalent to1 (mod 3), the equation=p+p(1)(2)+P-2(2)+(P3P42)-P-2, \p-(N)/(5\) less than or equal to root(N)/U-5, \pi -root(N)/(5\)less than or equal to U, i = 1, 2, 3, 4 has solutions, where U = N5/11+epsilon, p and p(i) are primes. Subject to the generalized Riemann hypothesis, U can be chosen as U = N2/5+epsilon.