The complete mitochondrial genome of the hybrid offspring Epinephelus fuscoguttatus ♀ x Epinephelus tukula ♂

被引：7

作者：

Cheng, Meiling ^{[1
,2
]}

Tian, Yongsheng ^{[1
,3
]}

Li, Zhentong ^{[1
,4
]}

Wang, Linna ^{[1
]}

Wu, Yuping ^{[1
,2
]}

Zhang, Jingjing ^{[1
,4
]}

Pang, Zunfang ^{[5
]}

Ma, Wenhui ^{[5
]}

Zhai, Jieming ^{[5
]}

机构：

[1] Chinese Acad Fishery Sci, Yellow Sea Fisheries Res Inst, Key Lab Sustainable Dev Marine Fisheries, Minist Agr & Rural Affairs, Qingdao 266071, Shandong, Peoples R China

[2] Dalian Ocean Univ, Coll Fisheries & Life Sci, Dalian, Peoples R China

[3] Qingdao Natl Lab Marine Sci & Technol, Lab Marine Fisheries Sci & Food Prod Proc, Qingdao, Shandong, Peoples R China

[4] Shanghai Ocean Univ, Coll Fisheries & Life Sci, Shanghai, Peoples R China

[5] Laizhou Mingbo Aquat Co Ltd, Yantai, Peoples R China

来源：

MITOCHONDRIAL DNA PART B-RESOURCES | 2019年 / 4卷 / 02期

关键词：

Mitochondrial genome; Epinephelus fuscoguttatus female x Epinephelus tukula male;

D O I：

10.1080/23802359.2019.1644554

中图分类号：

Q3 [遗传学];

学科分类号：

071007 ; 090102 ;

摘要：

The hybrid offspring Epinephelus fuscoguttatus female x E. tukula male showed heterosis in terms of growth and disease resistance. The mitochondrial genome is 16,629 bp in length and consists of 13 protein-coding genes, 2 rRNA genes, 22 tRNA genes, and a control region. The difference of total length is mainly caused by the difference of length in non-coding region. The nucleotide base composition is A = 29.15%, G = 15.62%, T = 26.91%, C = 28.32%, A + T = 56.06%, and C + G = 43.94%. The phylogenetic analysis using neighbour-joining (NJ) method showed that the hybrid offspring has a closer relationship to E. fuscoguttatus x E. lanceolatus.

引用

页码：2717 / 2718

页数：2

共 2 条

[1] MEGA5: Molecular Evolutionary Genetics Analysis Using Maximum Likelihood, Evolutionary Distance, and Maximum Parsimony Methods [J].