Rotational and vibrational state distributions of the OH radicals produced in the reaction O-16(D-1) + (H2O)-O-18 -->H-16 + (OH)-O-18 have been determined using a laser-induced fluorescence technique. O-16(D-1) was prepared by the 193 nm photodissociation of N2O. The rotational distributions for (OH)-O-16 and (OH)-O-18 in the v = 0 level are characterized by the Boltzmann temperatures of 6000 and 2600 K, respectively, A considerable amount of (OH)-O-16 exists in the v = 1 state while (OH)-O-18 was produced predominantly in the v = 0 state.