The Bohr operator on analytic functions and sections

被引:8
|
作者
Abu-Muhanna, Yusuf [1 ]
Ali, Rosihan M. [2 ]
Lee, See Keong [2 ]
机构
[1] Amer Univ Sharjah, Dept Math, Sharjah 26666, U Arab Emirates
[2] Univ Sains Malaysia, Sch Math Sci, Usm Penang 11800, Malaysia
关键词
Bohr radius; Rogosinski radius; Bohr operator; von Neumann inequality; Section of analytic functions; Subordination; SUBORDINATING FAMILIES; POWER-SERIES; RADIUS; THEOREM; INEQUALITY; CONJECTURE;
D O I
10.1016/j.jmaa.2020.124837
中图分类号
O29 [应用数学];
学科分类号
070104 ;
摘要
The Bohr operator M-r for a given analytic function f(z) = Sigma(infinity)(n=0) a(n)z(n) and a fixed zin the unit disk, vertical bar z vertical bar = r, is given by M-r (f) = Sigma(infinity)(n=0) vertical bar a(n)vertical bar vertical bar z(n)vertical bar = Sigma(infinity)(n=0) vertical bar a(n)vertical bar r(n). Applying earlier results of Bohr and Rogosinski, the Bohr operator is used to readily establish the following inequalities: if f(z) = Sigma(infinity)(n=0) a(n)z(n) is subordinate (or quasi-subordinate) to h(z) = Sigma(infinity)(n=0) b(n)z(n) in the unit disk, then M-r(f) <= M-r(h), 0 <= r <= 1/3. Further, each k-th section s(k)(f) = a(0) + a(1)z + ... + a(k)z(k) satisfies vertical bar s(k) (f)vertical bar <= M-r (s(k) (h)), 0 <= r <= 1/2, and M-r (s(k) (f)) <= M-r (s(k) (h)), 0 <= r <= 1/3. Both constants 1/2 and 1/3 cannot be improved. From these inequalities, a refinement of Bohr's theorem is obtained in the subdisk vertical bar z vertical bar <= 1/3. Also established are growth estimates in the subdisk of radius 1/2 for the k-th section s(k)(f) of analytic functions f subordinate to a concave wedge-mapping. A von Neumann-type inequality is established for the class consisting of Schwarz functions in the unit disk. (C) 2020 Elsevier Inc. All rights reserved.
引用
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页数:11
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