The equation n(n+d) ... (n+(k+1)d) = by2 with ω(d) ≤ 6 or d ≤ 1010

被引：13

作者：

Laishram, Shanta ^{[1
]}

Shorey, T. N. ^{[1
]}

机构：

[1] Tata Inst Fundamental Res, Bombay 400005, Maharashtra, India

来源：

ACTA ARITHMETICA | 2007年 / 129卷 / 03期

关键词：

diophantine equations; arithmetic progressions; squares; Legendre symbol; squarefree integers; congruences;

D O I：

10.4064/aa129-3-2

中图分类号：

O1 [数学];

学科分类号：

0701 ; 070101 ;

摘要：

[No abstract available]

引用

页码：249 / 305

页数：57

共 31 条

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[29] On the Diophantine equations of the form λ1Un1+λ2Un2+⋯+λkUnk=wp1z1p2z2⋯pszs\documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength{\oddsidemargin}{-69pt} \begin{document}$$\lambda _1U_{n_1} + \lambda _2U_{n_2} +\cdots + \lambda _kU_{n_k} = wp_1^{z_1}p_2^{z_2} \cdots p_s^{z_s}$$\end{document}
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[30] On the Lucas sequence equation 1Un=∑k=1∞Uk-1xk\documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength{\oddsidemargin}{-69pt} \begin{document}$$\frac{1}{U_n}=\sum _{k=1}^{\infty }\frac{U_{k-1}}{x^k}$$\end{document}
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