GROWTH CONDITIONS FOR ENTIRE FUNCTIONS WITH ONLY BOUNDED FATOU COMPONENTS

被引:8
作者
Hinkkanen, Aimo [1 ]
Miles, Joseph [1 ]
机构
[1] Univ Illinois, Dept Math, Urbana, IL 61801 USA
来源
JOURNAL D ANALYSE MATHEMATIQUE | 2009年 / 108卷
基金
美国国家科学基金会;
关键词
UNBOUNDED-DOMAINS; ITERATION; NORMALITY;
D O I
10.1007/s11854-009-0019-y
中图分类号
O1 [数学];
学科分类号
0701 ; 070101 ;
摘要
Let f be a transcendental entire function of order less than 1/2. Denote the maximum and minimum modulus of f by M(r, f) = max{|f(z)|: |z| = r} and m(r, f) = min{|f(z)|: |z| = r}. We obtain a minimum modulus condition satisfied by many f of order zero that implies all Fatou components are bounded. A special case of our result is that if log log M(r, f) = O(log r/log log r)(K)) for some K > 1, then there exist alpha > 1 and C > 0 such that for all large R, there exists r is an element of (R, R-alpha] with log m(r, f)/log m(R, f) >= alpha (1 - C/(log log R)(K)), and this in turn implies boundedness of all Fatou components. The condition on m(r, f) is a refined form of a minimum modulus conjecture formulated by the first author. We also show that there are some functions of order zero, and there are functions of any positive order, for which even refined forms of the minimum modulus conjecture fail. Our results and counterexamples indicate rather precisely the limits of the method of using the minimum modulus to rule out the existence of unbounded Fatou components.
引用
收藏
页码:87 / 118
页数:32
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