Dedekind sums take each value infinitely many times

For a is an element of Z and b is an element of N, (a, b) = 1, let s(a, b) denote the classical Dedekind sum. We show that, Dedekind sums take this value infinitely many times in the following sense. There are pairs (a(i), b(i)), i is an element of N, with b(i) tending to infinity as i grows, such that s(a(i), b(i)) = s(a, b) for all i is an element of N.